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Q. No.Two resistors of \(200~\Omega\) and \(400~\Omega\) are connected in series with a battery of \(100~\text{V}.\) A bulb rated at \(200~\text{V},100~\text{W}\) is connected across the \(400~\Omega\) resistance. The potential drop across the bulb is: (in \(\text{V}\))
1. \(25\)
2. \(50\)
3. \(66.6\)
4. \(100\)
1. \(25\)
2. \(50\)
3. \(66.6\)
4. \(100\)
Subtopic: Heating Effects of Current |
79%
Level 2: 60%+
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Two cells of emfs \(1~\text{V}\) and \(2~\text{V}\) and internal resistance \(2~\Omega\) and \(1~\Omega,\) respectively connected in parallel, gave a current of \(1~\text{A}\) through an external resistance. If the polarity of one cell is reversed, then value of current through the external resistance will be \(\dfrac{\alpha}{5} ~\text{A} .\) The value of \(\alpha\) is:
1. \(4\)
2. \(3\)
3. \(2\)
4. \(1\)
1. \(4\)
2. \(3\)
3. \(2\)
4. \(1\)
Subtopic: Grouping of Cells |
71%
Level 2: 60%+
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Refer to the circuit diagram given below. The heat generated across the \(6~\Omega\) resistance in \(100\) second is \(\dfrac{\alpha}{100}~\text{J}.\) The value of \(\alpha\) is: (Nearest integer)
1. \(32\)
2. \(35\)
3. \(39\)
4. \(45\)
1. \(32\)
2. \(35\)
3. \(39\)
4. \(45\)
Subtopic: Heating Effects of Current |
75%
Level 2: 60%+
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Refer the figure given below. The values of \(I_1 , I_2 ~\text{and} ~ I_3\) are:
1. \(I_{1} = 2.5~\text{A},~ I_{2} = 1.875~\text{A},~ I_{3} = 1.875~\text{A} \)
2. \( I_{1} = 1.875~\text{A},~ I_{2} = 2.5~\text{A},~ I_{3} = 1.875~\text{A}\)
3. \(I_{1} = 1.875~\text{A}, I_{2} = 1.875~\text{A}, ~ I_{3} = 2.5~\text{A}\)
4. \(I_{1} = 2.5~\text{A}~ I_{2} = 2.5~\text{A}, I_{3} = 1.875~\text{A}\)
1. \(I_{1} = 2.5~\text{A},~ I_{2} = 1.875~\text{A},~ I_{3} = 1.875~\text{A} \)
2. \( I_{1} = 1.875~\text{A},~ I_{2} = 2.5~\text{A},~ I_{3} = 1.875~\text{A}\)
3. \(I_{1} = 1.875~\text{A}, I_{2} = 1.875~\text{A}, ~ I_{3} = 2.5~\text{A}\)
4. \(I_{1} = 2.5~\text{A}~ I_{2} = 2.5~\text{A}, I_{3} = 1.875~\text{A}\)
Subtopic: Kirchoff's Current Law |
Level 3: 35%-60%
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Refer to the figure given below, current between terminals \(A\) and \(B\) is: (in \(A\))
1. \(12.5\)
2. \(1.25\)
3. \(7.5\)
4. \(5\)
1. \(12.5\)
2. \(1.25\)
3. \(7.5\)
4. \(5\)
Subtopic: Combination of Resistors |
80%
Level 1: 80%+
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In an experiment to determined the resistance of a given wire using Ohm's law, the voltmeter and ammeter readings are noted as \(10~\text{V}\) and \(5~\text{A}\), respectively The least counts of voltmeter and ammeter are \(500 ~\text{mV}\) and \(200~\text{mA}\), respectively. The estimated error in the resistance measurement is: (in \(\Omega\))
1. \(0.25 \)
2. \(2\)
3. \(2.5\)
4. \(0.18\)
1. \(0.25 \)
2. \(2\)
3. \(2.5\)
4. \(0.18\)
Subtopic: Derivation of Ohm's Law |
56%
Level 3: 35%-60%
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Under steady state condition the potential difference across the capacitor in the circuit is: (in \(\text{V}\))
1. \(0.5\)
2. \(1.5\)
3. \(0\)
4. \(2\)
1. \(0.5\)
2. \(1.5\)
3. \(0\)
4. \(2\)
Subtopic: Derivation of Ohm's Law |
54%
Level 3: 35%-60%
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When an external resistance of \(5~\Omega\) \(5~\Omega\) \(2~\Omega\)
1. \(4\)
2. \(2\)
3. \(1\)
4. \(3\)
1. \(4\)
2. \(2\)
3. \(1\)
4. \(3\)
Subtopic: Grouping of Cells |
Level 4: Below 35%
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The voltage and the current between \(A\) and \(B\) points shown in the circuit are:
1. \(24~\text{V},12~\text{A}\)
2. \(24~\text{V},4~\text{A}\)
3. \(18~\text{V},12~\text{A}\)
4. \(27~\text{V},4~\text{A}\)
1. \(24~\text{V},12~\text{A}\)
2. \(24~\text{V},4~\text{A}\)
3. \(18~\text{V},12~\text{A}\)
4. \(27~\text{V},4~\text{A}\)
Subtopic: Combination of Resistors |
70%
Level 2: 60%+
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The heat generated in \(1\) minute between points \(A\) and \(B\) in the given circuit, when a battery of \(9~\text{V}\) with internal resistance of \(1~\Omega\) is connected across these points is: (in J)
1. \(1080\)
2. \(1000\)
3. \(500\)
4. \(250\)
1. \(1080\)
2. \(1000\)
3. \(500\)
4. \(250\)
Subtopic: Wheatstone Bridge |
67%
Level 2: 60%+
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