Find the correct decreasing order of the reducing power of Al, Ag, K and Cr.
Given standard reduction potentials:

E°(Al³⁺/Al) = −1.66 V
E°(Ag⁺/Ag) = +0.80 V
E°(K⁺/K) = −2.93 V
E°(Cr³⁺/Cr) = −0.79 V

1. Ag>Cr>Al>K

2. K>Al>Cr>Ag

3. K>Al>Ag>Cr

4. Al>K>Ag>Cr

Which of the following processes is happening at the anode (from the options given below)?

1. \(\mathrm{F}_2+2 \mathrm{e}^{-} \rightarrow 2 \mathrm{~F}^{-}\)
2. \( \mathrm{H}^{+}+\frac{1}{2} \mathrm{O}_2+2 \mathrm{e}^{-} \rightarrow \mathrm{H}_2 \mathrm{O}\) 
3. \(2Cr^{3+}+7H_2O \rightarrow Cr_2O^{2-}_7 +14H^+ + 6e^-\)
4. None of the above

Which of the following is the strongest oxidising agent?

1. $Br{O}_3^{-}/B{r}^{2+},E^o=+1.50$

2. $F{e}^{3+}/F{e}^{2+},E^o=+0.76$

3. $Mn{O}_4^{-}/M{n}^{2+},E^o=+1.52$

4. $C{r}_2{O}_7^{2-}/C{r}^{3+},E^o=+1.33$