- 1(current)
Q. No.The mean free path for a gas, with molecular diameter \(d\) and number density \(n,\) can be expressed as:
| 1. | \( \dfrac{1}{\sqrt{2} n \pi {d}^2} \) | 2. | \( \dfrac{1}{\sqrt{2} n^2 \pi {d}^2} \) |
| 3. | \(\dfrac{1}{\sqrt{2} n^2 \pi^2 d^2} \) | 4. | \( \dfrac{1}{\sqrt{2} n \pi {d}}\) |
Subtopic: Â Mean Free Path |
 84%
Level 1: 80%+
NEET - 2020
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The mean free path \(l\) for a gas molecule depends upon the diameter, \(d\) of the molecule as:
| 1. | \(l\propto \dfrac{1}{d^2}\) | 2. | \(l\propto d\) |
| 3. | \(l\propto d^2 \) | 4. | \(l\propto \dfrac{1}{d}\) |
Subtopic: Â Mean Free Path |
 86%
Level 1: 80%+
NEET - 2020
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The mean free path of molecules of a gas (radius \(r\)) is inversely proportional to:
| 1. | \(r^3\) | 2. | \(r^2\) |
| 3. | \(r\) | 4. | \(\sqrt{r}\) |
Subtopic: Â Mean Free Path |
 85%
Level 1: 80%+
AIPMT - 2014
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- 1(current)
Q. No.
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