The relationship between force and position is shown in the given figure (in a one-dimensional case). The work done by the force in displacing a body from \(x = 1~\text{cm}\) to \(x = 5~\text{cm}\) is:
      
1. \(20~\text{ergs}\) 
2. \(60~\text{ergs}\)
3. \(70~\text{ergs}\) 
4. \(700~\text{ergs}\)

Subtopic:  Work Done by Variable Force |
 85%
Level 1: 80%+
Hints
Links

A position dependent force \(F=7-2x+3x^2\) N acts on a small body of mass \(2\) kg and displaces it from \(x = 0\) to \(x = 5\) m. The work done in joule is:

1. \(70\) 2. \(270\)
3. \(35\) 4. \(135\)
Subtopic:  Work Done by Variable Force |
 84%
Level 1: 80%+
Hints
Links

premium feature crown icon
Unlock IMPORTANT QUESTION
This question was bookmarked by 5 NEET 2025 toppers during their NEETprep journey. Get Target Batch to see this question.
✨ Perfect for quick revision & accuracy boost
Buy Target Batch
Access all premium questions instantly
A body is displaced from \((0,0)\) to \((1~\text{m}, 1~\text{m})\) along the path \(x=y\) by a force \(F = (x^2\hat j+y\hat i)~\text{N}.\) The work done by this force will be:
1. \(\frac{4}{3}~\text{J}\)
2. \(\frac{5}{6}~\text{J}\)
3. \(\frac{3}{2}~\text{J}\)
4. \(\frac{7}{5}~\text{J}\)

Subtopic:  Work Done by Variable Force |
 79%
Level 2: 60%+
Hints

advertisementadvertisement

When a body moves non-uniformly on a circular path:
1. no work is done by the tangential force.
2. no work is done by the centripetal force.
3. work done by the tangential force is always positive.
4. work done by the centripetal force is negative.
Subtopic:  Work Done by Variable Force |
 73%
Level 2: 60%+
Hints