Q. No.The heat generated in \(1\) minute between points \(A\) and \(B\) in the given circuit, when a battery of \(9~\text{V}\) with internal resistance of \(1~\Omega\) is connected across these points is: (in J)
1. \(1080\)
2. \(1000\)
3. \(500\)
4. \(250\)
1. \(1080\)
2. \(1000\)
3. \(500\)
4. \(250\)
Subtopic: Wheatstone Bridge |
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The total length of potentiometer wire \(AB\) is \(50~\text{cm}\) in the arrangement as shown in figure. If \(P\) is the point where the galvanometer shows zero reading then the length \(AP\) is: (in cm)
1. \(15\)
2. \(30\)
3. \(25\)
4. \(20\)
1. \(15\)
2. \(30\)
3. \(25\)
4. \(20\)
Subtopic: Wheatstone Bridge |
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A Wheatstone bridge is initially at room temperature and all arms of the bridge have same value of resistances \((R_1=R_2 = R_3=R_4)\). When \(R_3\) resistance is heated to some temperature, its resistance value has gone up by \(10\%\). The potential difference \((V_a \text-V_b)\) (after \(R_3\) is heated) is: (in V)
1. \(1.05\)
2. \(0\)
3. \(0.95\)
4. \(2\)
1. \(1.05\)
2. \(0\)
3. \(0.95\)
4. \(2\)
Subtopic: Wheatstone Bridge |
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For the given electrical circuit, the potential difference between point \(B\) and \(C\) is zero. The value of \(x\) is:
1. \(\dfrac{1}{2}\) \(\Omega\)
2. \(\dfrac{3}{2}\) \(\Omega\)
3. \(\dfrac{2}{3}\) \(\Omega\)
4. \(\dfrac{3}{5}\) \(\Omega\)
1. \(\dfrac{1}{2}\) \(\Omega\)
2. \(\dfrac{3}{2}\) \(\Omega\)
3. \(\dfrac{2}{3}\) \(\Omega\)
4. \(\dfrac{3}{5}\) \(\Omega\)
Subtopic: Wheatstone Bridge |
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In the circuit shown, the equivalent resistance between terminals \(A\) and \(B\) is:
1. \(3R/2\)
2. \(2R\)
3. \(4R\)
4. \(R\)
1. \(3R/2\)
2. \(2R\)
3. \(4R\)
4. \(R\)
Subtopic: Wheatstone Bridge |
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Current measured by the ammeter \(A\) in the reported circuit when no current flows through \(10~\Omega\) resistance will be:
1. \(20~\text{A}\)
2. \(30~\text{A}\)
3. \(10~\text{A}\)
4. \(0~\text{A}\)
1. \(20~\text{A}\)
2. \(30~\text{A}\)
3. \(10~\text{A}\)
4. \(0~\text{A}\)
Subtopic: Wheatstone Bridge |
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A battery of \(6\) V is connected to the circuit as shown below. The current \(i\) drawn from the battery is:
1. \(1\) A
2. \(2\) A
3. \(\frac{6}{11}~\text{A}\)
4. \(\frac{4}{3}~\text{A}\)
1. \(1\) A
2. \(2\) A
3. \(\frac{6}{11}~\text{A}\)
4. \(\frac{4}{3}~\text{A}\)
Subtopic: Wheatstone Bridge |
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Subtopic: Wheatstone Bridge |
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Four resistors of resistances \(15~ \Omega , 12~ \Omega , 4~ \Omega ,\) and \(10 ~\Omega \) are connected in cyclic order to form a Wheatstone network. To balance the network, an additional resistor is connected in parallel with the \(10 ~\Omega \) resistor. The value of this additional resistance should be:
1. \(10~\Omega\)
2. \(20~\Omega\)
3. \(30~\Omega\)
4. \(40~\Omega\)
Subtopic: Wheatstone Bridge |
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In the given circuit, an \(8~\text{V}\) battery powers a network of resistors. The current \(i_1\) flows from point \(A\) to point \(C\) through the resistor network. The value of \(i_1\) is:
1. \(2~\text{A}\)
2. \(1~\text{A}\)
3. \(5~\text{A}\)
4. \(4~\text{A}\)
Subtopic: Wheatstone Bridge |
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Level 3: 35%-60%
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