An instrument with a small least count will have definitely:
1. high accuracy and high precision
2. low accuracy and low precision
3. high accuracy
4. high precision
Subtopic:  Measurement & Measuring Devices |
From NCERT
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The speed of a distant star is observed to be \(1\) light-year/century. This value, when expressed in SI, is (approximately):
1. \(3\times10^8~\text{m/s}\)    2. \(3\times10^6~\text{m/s}\)   
3. \(3\times10^4~\text{m/s}\) 4. \(300~\text{m/s}\)
Subtopic:  Measurement & Measuring Devices |
From NCERT
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A screw gauge of pitch \(0.5\) mm is used to measure the diameter of uniform wire of length \(6.8\) cm, the main scale reading is \(1.5\) mm and circular scale reading is \(7\). The calculated curved surface area of wire to the appropriate significant figures is:
[Screw gauge has \(50\) divisions on the circular scale]
1. \(6.8\) cm2
2. \(3.4\) cm2
3. \(3.9\) cm2
4. \(2.4\) cm2
Subtopic:  Measurement & Measuring Devices |
 51%
From NCERT
JEE
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In a Vernier Calipers. \(10\) divisions of the Vernier scale is equal to the \(9\) divisions of the main scale. When both jaws of Vernier calipers touch each other, the zero of the Vernier scale is shifted to the left of zero of the main scale and \(4\)th Vernier scale division exactly coincides with the main scale reading. One main scale division is equal to \(1\) mm. While measuring diameter of a spherical body, the body is held between two jaws. It is now observed that zero of the Vernier scale lies between \(30\) and \(31\) divisions of main scale reading and \(6\)th Vernier scale division exactly coincides with the main scale reading. The diameter of the spherical body will be:
1. \(3.02~\text{cm}\)
2. \(3.06~\text{cm}\)
3. \(3.10~\text{cm}\)
4. \(3.20~\text{cm}\)
 
Subtopic:  Measurement & Measuring Devices |
 52%
From NCERT
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