An ideal gas is confined in a closed container and slowly heated. As the temperature rises, which of the following statements are correct?

(A) The mean free path of gas molecules decreases.
(B) The mean collision time between the molecules decreases.
(C) The mean free path remains unchanged.
(D) The mean collision time remains unchanged.

Choose the correct option from the given ones:
1. (C) and (D) only
2. (A) and (B) only
3. (A) and (D) only
4. (B) and (C) only
Subtopic:  Mean Free Path |
From NCERT
JEE
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If the ratio of the number density per cm3 of the two gases is \(5:3\) and the ratio of the diameters of the molecules of the two gases is \(4:5,\) then, the ratio of the mean free path of molecules of two gases is:

1. \(\dfrac{16}{15}\) 2. \(\dfrac{15}{16}\)
3. \(\dfrac{3}{4}\) 4. \(\dfrac{4}{3}\)
Subtopic:  Mean Free Path |
 72%
From NCERT
JEE
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According to the kinetic theory of gases,
(A)  the motion of the gas molecules freezes at \(0^\circ\text C.\)
(B) the mean free path of gas molecules decreases if the density of molecules is increased.
(C) the mean free path of gas molecules increases if the temperature is increased keeping the pressure constant.
(D) average kinetic energy per molecule per degree of freedom is \(\dfrac32k_B T\) (for monoatomic gases).
Choose the most appropriate answer from the options given below:
1. (A) and (C) only
2. (B) and (C) only
3. (A) and (B) only
4. (C) and (D) only
Subtopic:  Mean Free Path |
 59%
From NCERT
JEE
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NEET 2026 - Target Batch - Vital
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NEET 2026 - Target Batch - Vital

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