- 1(current)
Q. No.(Given : Atomic masses of \(\mathrm{C, H}\) and \(\mathrm{N}\) are \(12, 1\) and \(14\) amu respectively. The molar mass of the compound A is \(\mathrm{162 ~g ~mol^{–1}}\))
1. \(\mathrm{C_4H_6N_2}\)
2. \(\mathrm{C_2H_3N}\)
3. \(\mathrm{C_5H_7N}\)
4. \(\mathrm{C_{10}H_{14}N_2}\)
A compound consists of 54.2% carbon (C), 9.2% hydrogen (H), and 36.6% oxygen (O) by mass. The molar mass of the compound is 132 g/mol.
Determine the molecular formula of the compound.
(Given -Relative atomic masses: C = 12, H = 1, O = 16)
| 1. | \(\mathrm{C}_4 \mathrm{H}_9 \mathrm{O}_3\) | 2. | \(\mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_6\) |
| 3. | \(\mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_3\) | 4. | \(\mathrm{C}_4 \mathrm{H}_8 \mathrm{O}_2\) |
A gaseous hydrocarbon upon combustion gives 0.72 g of water and 3.08 g. of CO2. The empirical formula of the hydrocarbon is:
| 1. | C6H5 | 2. | C7H8 |
| 3. | C2H4 | 4. | C3H4 |
1. C5H7N
2. C10H14N2
3. C4H6N2
4. C2H3N
A solution of phenol in chloroform when treated with aqueous NaOH gives compound P as a major product. The mass percentage of carbon in P is:
(to the nearest integer) (Atomic mass : C =12; H=1; O=16)
| 1. | 65 | 2. | 69 |
| 3. | 73 | 4. | 76 |
Complex A has a composition of H12O6Cl3Cr . If the complex on treatment with concentrated H2SO4 loses 13.5% of its original mass, the correct molecular formula of A is :
[ Given: atomic mass of Cr = 52 amu and Cl =35 amu]
1. [Cr(H2O)5Cl]Cl2H2O
2. [Cr(H2O)6]Cl3
3. [Cr(H2O)3Cl3]3H2O
4. [Cr(H2O)4Cl2]Cl2H2O
1. \(\mathrm{C}_{11} \mathrm{H}_{22} \mathrm{O}_{12}\)
2. \(\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}\)
3. \(\mathrm{C}_{10} \mathrm{H}_{20} \mathrm{O}_{11}\)
4. \(\mathrm{C}_{11} \mathrm{H}_{22} \mathrm{O}_{11}\)
| 1. | 46% | 2. | 53% |
| 3. | 32% | 4. | 76% |
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Q. No.
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