- 1(current)
Q. No.In a series \(RLC\) circuit, \(R=80~\Omega\), \(X_L=100~\Omega\), \(X_C=40~\Omega\). If the source voltage is \(2500 \cos (628 t)\) V, the peak current is equal to:
1. \(5\) A
2. \(25 \) A
3. \(10\) A
4. \(12\) A
1. \(5\) A
2. \(25 \) A
3. \(10\) A
4. \(12\) A
Subtopic: RMS & Average Values |
82%
Level 1: 80%+
JEE
Please attempt this question first.
Hints
The current flowing through an AC circuit is given by
\(I=5 \sin (120 \pi t)~\text{A}\)
How long will the current take to reach the peak value starting from zero?
1. \(\frac{1}{60}~\text{s} \)
2. \(60~\text{s} \)
3. \(\frac{1}{120}~\text{s} \)
4. \(\frac{1}{240}~\text{s} \)
\(I=5 \sin (120 \pi t)~\text{A}\)
How long will the current take to reach the peak value starting from zero?
1. \(\frac{1}{60}~\text{s} \)
2. \(60~\text{s} \)
3. \(\frac{1}{120}~\text{s} \)
4. \(\frac{1}{240}~\text{s} \)
Subtopic: RMS & Average Values |
78%
Level 2: 60%+
JEE
Please attempt this question first.
Hints
Please attempt this question first.
An alternating current is given by the equation \(i=i_1\sin\omega t+i_2\cos \omega t\). The rms current will be:
1. \( \frac{1}{\sqrt{2}}\left(i_1^2+i_2^2\right)^{\frac{1}{2}} \)
2. \(\frac{1}{\sqrt{2}}\left(i_1+i_2\right)^2 \)
3. \( \frac{1}{2}\left(i_1^2+i_2^2\right)^{\frac{1}{2}} \)
4. \( \frac{1}{\sqrt{2}}\left(i_1+i_2\right) \)
Subtopic: RMS & Average Values |
76%
Level 2: 60%+
JEE
Please attempt this question first.
Hints
Please attempt this question first.
In the AC circuit shown in the figure, the value of \(I_{rms}\) is equal to:
1. \(2\) A
2. \(2\sqrt{2}\) A
3. \(4\) A
4. \(\sqrt{2}\) A
1. \(2\) A
2. \(2\sqrt{2}\) A
3. \(4\) A
4. \(\sqrt{2}\) A
Subtopic: RMS & Average Values |
73%
Level 2: 60%+
JEE
Please attempt this question first.
Hints
Find the peak current and resonant frequency of the following circuit (as shown in the figure).
1. \(0.2\) A and \(50\) Hz
2. \(0.2\) A and \(100\) Hz
3. \(2\) A and \(100\) Hz
4. \(2\) A and \(50\) Hz
Subtopic: RMS & Average Values |
62%
Level 2: 60%+
JEE
Please attempt this question first.
Hints
Please attempt this question first.
A direct current of \(4\) A and an alternating current of peak value \(4\) A flow through resistance of \(3~\Omega\) and \(2~\Omega\) respectively. The ratio of heat produced in the two resistances in same interval of time will be:
1. \(3:2\)
2. \(3:1\)
3. \(3:4\)
4. \(4:3\)
1. \(3:2\)
2. \(3:1\)
3. \(3:4\)
4. \(4:3\)
Subtopic: RMS & Average Values |
57%
Level 3: 35%-60%
JEE
Please attempt this question first.
Hints
Please attempt this question first.
- 1(current)
Q. No.
© 2025 GoodEd Technologies Pvt. Ltd.