Water from a tap emerges vertically downwards with an initial speed of \(1.0~\text{m/s}\). The cross-sectional area of the tap is \(10^{-4}~\text{m}^2\). Assume that the pressure is constant throughout the stream of water and that the flow is streamlined. The cross-sectional area of the stream, \(0.15~\text{m}\) below the tap would be: (Take \(g=10~\text{m/s}^2\))
1. \(5\times10^{-4}~\text{m}^2\)
2. \(2\times10^{-5}~\text{m}^2\)
3. \(5\times10^{-5}~\text{m}^2\)
4. \(1\times10^{-5}~\text{m}^2\)
A fluid is flowing through a horizontal pipe of varying cross-sections, with speed \(v\) ms-1 at a point where the pressure is \(P\) pascal. At another point where pressure is \(\dfrac{P}{2}\) pascal, its speed is \(V\) ms-1. If the density of the fluid is \(\rho\) kg-m-3 and the flow is streamlined, then \(V\) is equal to:
1. \(\sqrt{\dfrac{P}{2\rho }+v^{2}}\)
2. \(\sqrt{\dfrac{P}{\rho }+v^{2}} \)
3. \(\sqrt{\dfrac{2P}{\rho }+v^{2}}\)
4. \(\sqrt{\dfrac{P}{\rho }+v^{}}\)
