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Q. No.Determine the minimum energy that must be possessed by photons in order to produce the photoelectric effect with platinum metal:
[Given: The threshold frequency of platinum is \(1.3\times10^{15}\text{s}^{-1}\) and \(\text{h}=6.6\times10^{-34}~\text{Js}.]\)
[Given: The threshold frequency of platinum is \(1.3\times10^{15}\text{s}^{-1}\) and \(\text{h}=6.6\times10^{-34}~\text{Js}.]\)
| 1. | \(3.21\times 10^{-14}~\text{J}\) | 2. | \(6.24\times 10^{-16}~\text{J}\) |
| 3. | \(8.58\times 10^{-19}~\text{J}\) | 4. | \(9.76\times 10^{-20}~\text{J}\) |
Subtopic: Photo Electric Effect |
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Level 1: 80%+
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The threshold frequency of a metal is \(1.4 \times 10^{15}sec^{-1}\). Calculate the minimum energy required to eject a photoelectron from this metal.
[Given: Planck’s constant, \(h = 6.6 \times 10^{-34} J sec\)]
2. \(9.24 \times 10^{-18}J \)
3. \(4.62 \times 10^{-19}J \)
4. \(4.62 \times 10^{-18}J \)
Subtopic: Photo Electric Effect |
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A source of monochromatic radiation of wavelength \(400~ nm\) provides \(1000 ~J\) of energy in \(10\) seconds. When this radiation falls on the surface of sodium, \(x\times 10^{20}\) electrons are ejected per second. Assume that wavelength \(400 ~nm\) is sufficient for ejection of electron from the surface of sodium metal. The value of \(x\) is: (Nearest integer)
[Given: \(h = 6.626 \times 10^{–34}~ Js\)]
1. Four (4)
2. Two (2)
3. Six (6)
4. Eight (8)
[Given: \(h = 6.626 \times 10^{–34}~ Js\)]
1. Four (4)
2. Two (2)
3. Six (6)
4. Eight (8)
Subtopic: Photo Electric Effect |
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Level 1: 80%+
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If the threshold wavelength () for the ejection of an electron from metal is 330 nm, then determine the work function for the photoelectric emission:
1. 1.2 × 10–18 J
2. 1.2 × 10–20 J
3. 6 × 10–19 J
4. 6 × 10–12 J
Subtopic: Photo Electric Effect |
84%
Level 1: 80%+
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