Aluminium becomes passive in nitric acid because it-

1. Is a noble metal

2. Forms a thin film of oxide

3. Has a positive reduction potential

4.  None of the above

The stability of the +1 oxidation state increases in the sequence:

1. Al <Ga<In<Tl

2. Tl<In<Ga<Al

3. In<Tl<Ga<Al

4. Ga<In<Al<Tl

Borax bead test is responded by:

1.  Divalent metals

2.  Heavy metals

3.  Light metals

4.  Metal which forms coloured metaborates

Match the species given in Column I with the properties mentioned in Column II.

Codes:

Aluminium chloride in acidified aqueous solution forms a complex 'A'.
The formula of A and hybridisation state of Al in 'A' is respectively:

1. [Al(H₂O)₆]³⁺, sp³d²

2. [Al(H₂O)₄]³⁺, sp³

3. [Al(H2O)4]3+, dsp2

4. [Al(H₂O)]³⁺, d²sp³

Match the species given in Column I with properties given in Column II.

Ionization enthalpy (${∆}_{\mathrm{i}}{\mathrm{H}}_1\mathrm{kJ}<mspace\; width="1em"></mspace>{\mathrm{mol}}^{-1}$) for the elements of Group 13 follows the order.

Aluminium reacts with concentrated HCl and concentrated NaOH to liberate which of the following gases respectively-

The correct order of atomic radii of the group 13 elements is-

1. B < Al < In < Ga < Tl
2. B < Al < Ga < In < Tl
3. B < Ga < Al < Tl < In
4. B < Ga < Al < In < Tl

${\mathrm{AlCl}}_3$ on hydrolysis gives -

1. ${\mathrm{Al}}_2{\mathrm{O}}_3.{\mathrm{H}}_2\mathrm{O}$

2. $\mathrm{Al}{\left(\mathrm{OH}\right)}_3$

3. ${\mathrm{Al}}_2{\mathrm{O}}_3$

4. ${\mathrm{AlCl}}_3.6{\mathrm{H}}_2\mathrm{O}$