The element from group 15 that forms a strong bond with hydrogen is:
| 1. | N | 2. | P | 
| 3. | As | 4. | Sb | 
PH3 forms bubbles when passed slowly through water but NH3 gets dissolved in water, because:
| 1. | NH3 forms an H-bond with water, so it is soluble but PH3 does not form an H-bond. | 
| 2. | NH3 does not form an H-bond with water, so it is soluble but PH3 does form an H-bond. | 
| 3. | NH3 and PH3 both form H-bond with water. | 
| 4. | NH3 and PH3 both do not form H-bond with water. | 
The bonding present in nitrogen molecules is:
1. \(p\pi-p\pi\)
2. \(p\pi-d\pi\)
3. \(d\pi-d\pi\)
4. Only sigma bond
An element that does not have a d-orbital is:
| 1. | P | 2. | N | 
| 3. | As | 4. | Bi | 
NH3 forms a hydrogen bond but PH3 does not because:
| 1. | Phosphorus is more electronegative as compared to nitrogen. | 
| 2. | Nitrogen is more electronegative as compared to phosphorus. | 
| 3. | Nitrogen and phosphorous have equal electronegativity. | 
| 4. | Nitrogen is more stable as compared to phosphorus. | 
Match the formulas of oxides given in Column I with the type of oxide given in Column II and mark the correct option.
| Column I | Column II | 
| A. Pb3O4 | 1. Neutral oxide | 
| B. N2O | 2. Acidic oxide | 
| C. Mn2O7 | 3. Basic oxide | 
| D. Bi2O3 | 4. Mixed oxide | 
Codes
| A | B | C | D | |
| 1. | 1 | 2 | 3 | 4 | 
| 2. | 4 | 1 | 2 | 3 | 
| 3. | 3 | 2 | 4 | 1 | 
| 4. | 4 | 3 | 1 | 2 | 
The respective oxidation states of P in H4P2O5, H4P2O6, and H4P2O7 are:
| 1. | +3, +5, and +4 | 2. | +5, +3, and +4 | 
| 3. | +5, +4, and +3 | 4. | +3, +4, and +5 | 
A balanced chemical equation for the reaction showing catalytic oxidation of NH3 by atmospheric oxygen is:
| 1. | 4NH3 + \(\underset{\text{From air}}{5O_2} \) \(\xrightarrow[\text{500 K; 9 bar}]{\text{Pt / Rh gauge catalyst}}\) 4NO + 6H2O | 
| 2. | 3NH4 + \(\underset{\text{From air}}{5O_2} \) \(\xrightarrow[\text{500 K; 9 bar}]{\text{Pt / Rh gauge catalyst}}\) 3NO + 6H2O | 
| 3. | 4NH3 + \(\underset{\text{From air}}{5O_2} \) \(\xrightarrow[\text{cold}]{\text{no catalyst}}\) 4NO + 6H2O | 
| 4. | 3NH4 + \(\underset{\text{From air}}{5O_2} \) \(\xrightarrow[\text{cold}]{\text{no catalyst}}\) 3NO + 6H2O | 
An element belongs to group 15 and 3rd period of the periodic table. Its electronic configuration would be:
1. \(\mathrm{1 s^2 2 s^2 2 p^4}
\)
2. \(\mathrm{1 s^2 2 s^2 2 p^3}
\)
3. \(\mathrm{1 s^2 2 s^2 2 p^6 3 s^2 3 p^2}
\)
4. \(\mathrm{1 s^2 2 s^2 2 p^6 3 s^2 3 p^3}\)
Nitrogen gas is liberated by the thermal decomposition of:
1.
2.
3.
4. All of the above.