- 1(current)
Q. No.The oxidizing power of chlorine in an aqueous solution can be determined by the following parameters:
\(\small{\frac{1}{2} \left(Cl\right)_{2} \left(g\right) \overset{\frac{1}{2} \left(\Delta\right)_{diss} H^{\Theta}}{\longrightarrow} Cl \left(g\right) \overset{\left(\Delta\right)_{eg} H^{\Theta}}{\longrightarrow} \left(Cl\right)^{-} \left(g\right) \overset{\left(\Delta\right)_{hyd} H^{\Theta}}{\longrightarrow} \left(Cl\right)^{-} \left(aq\right)}\)
The energy involved in the conversion of \({ 1 \over 2}Cl_2(g)\) to \(Cl^-\)(aq) will be:
Use the following data:
\(\Delta_{\text {diss }} H^{\circ}\left(\mathrm{Cl}_2\right)=240 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
\(\Delta_{\mathrm{eg}} H^{\circ}(\mathrm{Cl})=-349 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
\(\Delta_{\mathrm{hyd}} H^{\circ}\left(\mathrm{Cl}^{-}\right)=-381 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
\(\small{\frac{1}{2} \left(Cl\right)_{2} \left(g\right) \overset{\frac{1}{2} \left(\Delta\right)_{diss} H^{\Theta}}{\longrightarrow} Cl \left(g\right) \overset{\left(\Delta\right)_{eg} H^{\Theta}}{\longrightarrow} \left(Cl\right)^{-} \left(g\right) \overset{\left(\Delta\right)_{hyd} H^{\Theta}}{\longrightarrow} \left(Cl\right)^{-} \left(aq\right)}\)
The energy involved in the conversion of \({ 1 \over 2}Cl_2(g)\) to \(Cl^-\)(aq) will be:
Use the following data:
\(\Delta_{\text {diss }} H^{\circ}\left(\mathrm{Cl}_2\right)=240 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
\(\Delta_{\mathrm{eg}} H^{\circ}(\mathrm{Cl})=-349 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
\(\Delta_{\mathrm{hyd}} H^{\circ}\left(\mathrm{Cl}^{-}\right)=-381 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
| 1. | - 610 kJ mol-1 | 2. | - 850 kJ mol-1 |
| 3. | +120 kJ mol-1 | 4. | +152 kJ mol-1 |
Subtopic: Hess's Law |
85%
Level 1: 80%+
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The value \(|\Delta H| \) in kJ for the given reaction is:
\(\frac{1}{2} C l_2(g) → C l^{-}(a q) \)
(Given: \(\Delta H_{\text {diss }} C l_2(g) → 2 C l(g) \quad 240 \mathrm{~kJ} \mathrm{mol}^{-1} \)
\(\Delta H_{eg} Cl(g) + e^- → Cl^-(g) -320~ \mathrm{ kJmol}^{-1}\\ \Delta H_{hydration} Cl^-(g) + aq → Cl^-(aq) -340~\mathrm{ kJmol}^{-1} ) \)
\(\frac{1}{2} C l_2(g) → C l^{-}(a q) \)
(Given: \(\Delta H_{\text {diss }} C l_2(g) → 2 C l(g) \quad 240 \mathrm{~kJ} \mathrm{mol}^{-1} \)
\(\Delta H_{eg} Cl(g) + e^- → Cl^-(g) -320~ \mathrm{ kJmol}^{-1}\\ \Delta H_{hydration} Cl^-(g) + aq → Cl^-(aq) -340~\mathrm{ kJmol}^{-1} ) \)
| 1. | 540 | 2. | 620 |
| 3. | 450 | 4. | 470 |
Subtopic: Hess's Law |
82%
Level 1: 80%+
Please attempt this question first.
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- 1(current)
Q. No.
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