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Q. No.In the part of a circuit shown, the ratio of the rate of heat produced in R to that in 3R is:
1. 1: 9
2. 1: 3
3. 3: 1
4. 9: 1
Subtopic: Heating Effects of Current |
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Level 2: 60%+
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For the given electrical circuit, the potential difference between point \(B\) and \(C\) is zero. The value of \(x\) is:
1. \(\dfrac{1}{2}\) \(\Omega\)
2. \(\dfrac{3}{2}\) \(\Omega\)
3. \(\dfrac{2}{3}\) \(\Omega\)
4. \(\dfrac{3}{5}\) \(\Omega\)
1. \(\dfrac{1}{2}\) \(\Omega\)
2. \(\dfrac{3}{2}\) \(\Omega\)
3. \(\dfrac{2}{3}\) \(\Omega\)
4. \(\dfrac{3}{5}\) \(\Omega\)
Subtopic: Wheatstone Bridge |
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Level 1: 80%+
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In the circuit shown below, the value of current \(I_1\) (in amperes) is equal to:
1. \(-{{11}\over{5}}\)
2. \({{11}\over{5}}\)
3. \(-{{5}\over{7}}\)
4. \({{5}\over{7}}\)
1. \(-{{11}\over{5}}\)
2. \({{11}\over{5}}\)
3. \(-{{5}\over{7}}\)
4. \({{5}\over{7}}\)
Subtopic: Kirchoff's Voltage Law |
Level 3: 35%-60%
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If \(n:\) number density of charge carriers.
\(A:\) cross-sectional area of the conductor
\(q:\) charge on each charge carrier
\(I:\) current through the conductor
Then the expression of drift velocity is:
1. \(\frac{nAq}{I}\)
2. \(\frac{I}{nAq}\)
3. \({nAqI}\)
4. \(\frac{IA}{nq}\)
\(A:\) cross-sectional area of the conductor
\(q:\) charge on each charge carrier
\(I:\) current through the conductor
Then the expression of drift velocity is:
1. \(\frac{nAq}{I}\)
2. \(\frac{I}{nAq}\)
3. \({nAqI}\)
4. \(\frac{IA}{nq}\)
Subtopic: Current & Current Density |
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Level 1: 80%+
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A conductor of length \(l\) and cross-sectional are \(A\) has drift velocity \(v_d\) when used across a potential difference \(V\).
When another conductor of the same material and length \(l\) but double cross-sectional area than the first, is used across
the same potential difference then drift velocity is equal to:
1. \(\frac{v_d}{2}\)
2. \(v_d\)
4. \(2v_d\)
4. \(4v_d\)
When another conductor of the same material and length \(l\) but double cross-sectional area than the first, is used across
the same potential difference then drift velocity is equal to:
1. \(\frac{v_d}{2}\)
2. \(v_d\)
4. \(2v_d\)
4. \(4v_d\)
Subtopic: Current & Current Density |
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Level 2: 60%+
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The current through a \(5~\Omega\) resistance remains the same, irrespective of its connection across a series or parallel combination of two identical cells. The internal resistance of the cell is:
1. \(5~\Omega\)
2. \(10~\Omega\)
3. \(15~\Omega\)
4. \(20~\Omega\)
1. \(5~\Omega\)
2. \(10~\Omega\)
3. \(15~\Omega\)
4. \(20~\Omega\)
Subtopic: Grouping of Cells |
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When current of \(4\) A is made to run through a resistance of \(R\) ohms for \(10\) s, it produces heat energy of \(H\) units. Now if \(16\) A of current is made to flow through the same resistance for \(10\) s then the heat energy produced will be:
1. \(16H\)
2. \(4H\)
3. \(8H\)
4. \(2H\)
1. \(16H\)
2. \(4H\)
3. \(8H\)
4. \(2H\)
Subtopic: Heating Effects of Current |
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Level 1: 80%+
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Consider a network of resistors as shown. The effective resistance across \(A\) and \(B\) is given by:
1. \(5~ \Omega\)
2. \(3~ \Omega\)
3. \(9~ \Omega\)
4. \(1~ \Omega\)
1. \(5~ \Omega\)
2. \(3~ \Omega\)
3. \(9~ \Omega\)
4. \(1~ \Omega\)
Subtopic: Combination of Resistors |
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What is the equivalent resistance of the given circuit across the terminals of ideal battery?
1. \(2R\)
2. \(3R\)
3. \(4R\)
4. \(5R\)
1. \(2R\)
2. \(3R\)
3. \(4R\)
4. \(5R\)
Subtopic: Combination of Resistors |
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In the circuit shown, The current through \(R_{4}~(I_{4})\) and \(R_{5}~(I_{5})\) is:
| 1. | \(I_4=\dfrac{24}{55}~\text{A},~\text{and} ~I_5 = \dfrac{96}{55}~\text{A}\) |
| 2. | \(I_4=\dfrac{96}{55}~\text{A},~\text{and} ~I_5 = \dfrac{24}{55}~\text{A}\) |
| 3. | \(I_4=\dfrac{24}{37}~\text{A},~\text{and}~ I_5 = \dfrac{96}{37}~\text{A}\) |
| 4. | \(I_4=\dfrac{96}{37}~\text{A},~\text{and} ~I_5 = \dfrac{24}{37}~\text{A}\) |
Subtopic: Combination of Resistors |
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Level 2: 60%+
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