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Q. No.Given below are two statements:
| Statement-1: | Electrical discharge is passed through the \(H_2\) gas. \(H_2\) dissociates into H atoms & the energetically excited atoms emit discrete frequencies. |
| Statement-2: | The frequency of the second line of the Balmer series is equal to the frequency of the first line of the Lyman series for the hydrogen atom. |
| 1. | Both the statements are correct. |
| 2. | Both the statements are incorrect. |
| 3. | Statement-1 is correct and statement-2 is incorrect. |
| 4. | Statement-1 is incorrect and statement-2 correct. |
Subtopic: Type of Spectra |
Level 4: Below 35%
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An electron in a hydrogen-like atom undergoes various transitions, resulting in the emission of photons corresponding to different spectral lines.
Arrange the following emitted photons in increasing order of their energy :
(A) 1st line of Lyman Series
(B) 2nd line of Balmer Series
(C) 3rd line of Paschen Series
(D) 4th line of Brackett Series
| 1. | D > A > B > C | 2. | A > B > C > D |
| 3. | B > C > D > A | 4. | A > B > D> C |
Subtopic: Type of Spectra |
84%
Level 1: 80%+
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Line corresponding to lyman series are \(L_1,L_2,L_3,L_4.....,\) among these \(L_1\) line corresponds to lowest energy. Similarly lines corresponding to balmer series are \(B_1,B_2,B_3,B_4....,\) among these \(B_1\) line corresponds to lowest energy:
\(\Delta E_L\) = Energy of \(1^{st}\) line of lyman series
\(\Delta E_B\) = Energy of \(1^{st}\) line of balmer series
If \(\Delta E_L=x.\Delta E_B\). Calculate \((x\times 10^{-1})\):
1. 54
2. 27
3. 40
4. 18
\(\Delta E_L\) = Energy of \(1^{st}\) line of lyman series
\(\Delta E_B\) = Energy of \(1^{st}\) line of balmer series
If \(\Delta E_L=x.\Delta E_B\). Calculate \((x\times 10^{-1})\):
1. 54
2. 27
3. 40
4. 18
Subtopic: Electromagnetic Radiation | Type of Spectra |
66%
Level 2: 60%+
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If for \(Li^{2+} \) ion, electron is in transition between energy levels such that sum of principal quantum numbers is 4 and difference is 2 then find the wavelength (in cm) emitted for transition between these energy levels
[Given: \(R_H = 1.1 \times 10^5 \text {cm}^{-1}\)]
1. \(114 \times 10^{-8} ~\text {cm}\)
2. \(1026 \times 10^{-8} ~\text {cm}\)
3. \(12.66 \times 10^{-8} ~\text {cm}\)
4. \( 10^{-8} ~\text {cm}\)
[Given: \(R_H = 1.1 \times 10^5 \text {cm}^{-1}\)]
1. \(114 \times 10^{-8} ~\text {cm}\)
2. \(1026 \times 10^{-8} ~\text {cm}\)
3. \(12.66 \times 10^{-8} ~\text {cm}\)
4. \( 10^{-8} ~\text {cm}\)
Subtopic: Bohr's Theory |
65%
Level 2: 60%+
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Heat of atomisation of \(CH_4(g) \) and \(C_2H_6(g)\) are x kJ/mole and y kJ/mole. Find the maximum wavelength of photon required to dissociate (C–C) bond in \(C_2H_6\):
1. \(\frac{\mathrm{hcN}_{\mathrm{A}}}{\left[\mathrm{y}-\frac{3 \mathrm{x}}{2}\right]} \)
2. \(\frac{\mathrm{hcN}_{\mathrm{A}}}{\left[\frac{4 \mathrm{x}-6 \mathrm{y}}{4}\right]} \)
3. \(\frac{\mathrm{hcN}_{\mathrm{A}}}{250\left[\frac{3 \mathrm{x}}{2}-\mathrm{y}\right]} \)
4. \(\frac{\mathrm{hcN}_{\mathrm{A}}}{500[2 \mathrm{y}-3 \mathrm{x}]}\)
1. \(\frac{\mathrm{hcN}_{\mathrm{A}}}{\left[\mathrm{y}-\frac{3 \mathrm{x}}{2}\right]} \)
2. \(\frac{\mathrm{hcN}_{\mathrm{A}}}{\left[\frac{4 \mathrm{x}-6 \mathrm{y}}{4}\right]} \)
3. \(\frac{\mathrm{hcN}_{\mathrm{A}}}{250\left[\frac{3 \mathrm{x}}{2}-\mathrm{y}\right]} \)
4. \(\frac{\mathrm{hcN}_{\mathrm{A}}}{500[2 \mathrm{y}-3 \mathrm{x}]}\)
Subtopic: Electromagnetic Radiation |
Level 4: Below 35%
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Energy of \(1^{st}\) Balmer line of H-atom is x J. The energy (in J) of second Balmer line of H-atom is :
1. x
2. 2x
3. 1.35x
4. \(\dfrac{\mathrm{x}}{1.35}\)
1. x
2. 2x
3. 1.35x
4. \(\dfrac{\mathrm{x}}{1.35}\)
Subtopic: Electromagnetic Radiation | Type of Spectra |
75%
Level 2: 60%+
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On two metal surfaces, a monochromatic light of 6 eV was incident. They have ratio of their work function and maximum KE as
\(\frac{\phi_1}{\phi_2}=\frac{1}{2}, \frac{\left(\mathrm{KE}_{\max }\right)_1}{\left(\mathrm{KE}_{\max }\right)_2}=\frac{2.62}{1}\)
Then \(\phi_1\) and \(\phi_2\) values are respectively (in eV):
1. 2.292, 4.584
2. 4.584, 2.292
3. 4.584, 9.168
4. 1.146, 2.292
\(\frac{\phi_1}{\phi_2}=\frac{1}{2}, \frac{\left(\mathrm{KE}_{\max }\right)_1}{\left(\mathrm{KE}_{\max }\right)_2}=\frac{2.62}{1}\)
Then \(\phi_1\) and \(\phi_2\) values are respectively (in eV):
1. 2.292, 4.584
2. 4.584, 2.292
3. 4.584, 9.168
4. 1.146, 2.292
Subtopic: Photo Electric Effect | Electromagnetic Radiation |
56%
Level 3: 35%-60%
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Which of the following are isobars?
1. \({ }_{92}^{232} \mathrm{U}\) and \({ }_{92}^{238} \mathrm{U}\)
2. \({ }_1^3 \mathrm{H}\) and \({ }_1^2 \mathrm{H} \)
3. \({ }_1^3 \mathrm{H}\) and \({ }_2^3 \mathrm{He}\)
4. \({ }_7^{14} \mathrm{~N}\) and \({ }_7^{15} \mathrm{~N}\)
1. \({ }_{92}^{232} \mathrm{U}\) and \({ }_{92}^{238} \mathrm{U}\)
2. \({ }_1^3 \mathrm{H}\) and \({ }_1^2 \mathrm{H} \)
3. \({ }_1^3 \mathrm{H}\) and \({ }_2^3 \mathrm{He}\)
4. \({ }_7^{14} \mathrm{~N}\) and \({ }_7^{15} \mathrm{~N}\)
Subtopic: Number of Electron, Proton & Neutron |
86%
Level 1: 80%+
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Which of the following is correct match for hydrogen like species for the total energy of \(e^-\)?
| Species and Orbit | Energy (J/atom) | |
| 1. | \(3^{rd}\) orbit of \(Li^{2+}\) ion | \( -21.6 \times 10^{-19} \) |
| 2. | \(2^{nd}\) orbit of \(He^{+}\) ion | \( -10.8 \times 10^{-19}\) |
| 3. | \(2^{nd}\) orbit of \(Li^{2+}\) ion | \( -9.6 \times 10^{-19} \) |
| 4. | \(2^{nd}\) orbit of H-atom | \( -86.4 \times 10^{-19} \) |
Subtopic: Introduction of Atomic Structure | Hydrogen Spectra |
68%
Level 2: 60%+
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The maximum number of electrons in the following two given set of quantum numbers respectively is :-
(i) n=5, \(m_l\) = –1
(ii) \(\mathrm{n}=4, \ell=2, \mathrm{~m}_{\ell}=1, \mathrm{~m}_{\mathrm{s}}=\frac{1}{2}\)
1. 8, 1
2. 4, 1
3. 26, 2
4. 10, 2
(i) n=5, \(m_l\) = –1
(ii) \(\mathrm{n}=4, \ell=2, \mathrm{~m}_{\ell}=1, \mathrm{~m}_{\mathrm{s}}=\frac{1}{2}\)
1. 8, 1
2. 4, 1
3. 26, 2
4. 10, 2
Subtopic: Quantum Numbers & Schrodinger Wave Equation |
63%
Level 2: 60%+
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