A particle is projected at an angle \(๐
ย \) with the horizontal with an initial speed \(u\). When it makes an angle \(๐ผ\) with the horizontal, its speed \(v\) is:
1. \(๐ข
\cos
๐\)
2. \(๐ข
\cos
๐
\ ๐ข
\cos
๐ผ
\)
3. \(\dfrac{u\sin \theta}{\sin \alpha}\)
4. \(\dfrac{u\cos \theta}{\cos \alpha}\)
A particle is moving along the path y = from x = 0 m to x = 2 m. Then the distance traveled by the particle is:
1. 4 m
2.
3.
4.
A body is projected with velocity \(20\sqrt3 \text{ ย m/s}\) with an angle of projection \(60^ยฐ\) with the horizontal. The velocity at the point where the body makes an angle \(30^ยฐ ย \)with the horizontal is:
1. \(20 \text{ ย m/s}\)
2. \(\dfrac{20}{\sqrt3} \text{ ย m/s}\)
3. \(10\sqrt3 \text{ ย m/s}\)
4. \(10 \text{ ย m/s}\)
In a uniform circular motion, which of the following quantity is not constant
1. Angular momentum
2. Speed
3. Kinetic energy
4. Momentum
A particle projected with kinetic energy with an angle of projection . Then the variation of kinetic K with vertical displacement y is
1. linear
2. parabolic
3. hyperbolic
4. periodic
A body is projected with a velocity \(u\) with an angle of projection \(\theta.\) The change in velocity after the time \((t)\) from the time of projection will be:
| 1. | \(gt\) | 2. | \(\frac{1}{2}gt^2\) |
| 3. | \(u\sin\theta\) | 4. | \(u\cos\theta\) |
A particle has initial velocity and has acceleration . Its speed after 10 s:
1. 7 units
2. units
3. 8.5 units
4. 10 units
The gravity in space is given by \(\vec g=-10 \hat j\ \text{m/s}^{2}\). Two particles are simultaneously projected with velocity \(\vec u_1=10\ \text{m/s} \hat i+10\ \text{m/s} \hat j\) and \(\vec u_2=20\ \text{m/s} \hat i+10\ \text{m/s} \hat j\). Then, the ratio of their times of flight is:
1. \(1:1\)
2. \(1:2\)
3. \(2:1\)
4. None of the above
What determines the nature of the path followed by the particle?
1. Speed only
2. Velocity only
3. Acceleration only
4. None of these
A boat is sent across a river in a perpendicular direction with a velocity of \(8\ \text{km/hr}\). If the resultant velocity of the boat is \(10\ \text{km/hr}\), then the velocity of the river is:
1. \(10\ \text{km/hr}\)
2. \(8\ \text{km/hr}\)
3. \(6\ \text{km/hr}\)
4. \(4\ \text{km/hr}\)