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The tension at the mid-point \(\mathrm{P}\) of the rope is:
(consider the system is in equilibrium condition, mass of rope\(=4~\) kg and \(g=10\) m/s2.
               
1. \(100\)
2. \(120\)
3. \(140\)
4. \(190\) N

Subtopic:  Tension & Normal Reaction |
 81%
Level 1: 80%+
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A disc revolves with a speed of \(0.5\) revolutions per second and has a radius of \(15\) cm. Two coins are placed at \(3\) cm and \(12\) cm away from the center. If the coefficient of friction between coins and the disc is \(0.2,\) then:
 
1. coin at \(3\) cm will slip.
2. coin at \(12\) cm will slip.
3. both coins will slip.
4. no coin will slip.
Subtopic:  Friction |
Level 3: 35%-60%
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The system is at rest initially, due to the force of friction acting on \(A\). If the string connecting the lower blocks is cut, the accelerations of the blocks \(A\), \(B\) & \(C\) will be, respectively,
   
1. \(\dfrac g 3\) to left, \(g\) upward, \(g\) downward.
2. zero, zero, \(g\) downward.
3. zero, \(g\) upward, \(g\) downward.
4. \(g\) to right, zero, \(g\) downward.
Subtopic:  Spring Force |
 68%
Level 2: 60%+
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When a body of mass \(m\) just begins to slide as shown, match List-I with List-II:

List-I List-II
(a) Normal reaction (i) \(P\)
(b) Frictional force \((f_s)\) (ii) \(Q\)
(c) Weight \((mg)\) (iii) \(R\)
(d) \(mg \mathrm{sin}\theta ~\) (iv) \(S\)

Choose the correct answer from the options given below:
(a) (b) (c) (d)
1. (ii) (i) (iii) (iv)
2. (iv) (ii) (iii) (i)
3. (iv) (iii) (ii) (i)
4. (ii) (iii) (iv) (i)
Subtopic:  Application of Laws |
 86%
Level 1: 80%+
NEET - 2022
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Given below are two statements: 
Assertion (A): Improper banking of roads causes wear and tear of tyres.
Reason (R): The necessary centripetal force in that event is provided by the force of friction between the tyres and the road.
  
1. Both (A) and (R) are True and (R) is the correct explanation of (A).
2. Both (A) and (R) are True but (R) is not the correct explanation of (A).
3. (A) is True but (R) is False.
4. Both (A) and (R) are False.
Subtopic:  Banking of Roads |
 70%
Level 2: 60%+
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It is given that the block never loses contact (in the figure given below)  with the smooth horizontal surface, and the force always acts at an angle \(\theta\) with the horizontal. The speed of the block when it covers a horizontal distance \(l\) will be:
1. \(\sqrt{\dfrac{l F_{} \cos \theta}{m}}\) 2. \(\dfrac{2 l \mathrm{~F}_{} \cos \theta}{\mathrm{m}}\)
3. \(\sqrt{\dfrac{2 l}{m} F_{} \cos \theta}\) 4. \(\dfrac{l \mathrm{~F}_{} \cos \theta}{\mathrm{m}}\)
Subtopic:  Application of Laws |
 86%
Level 1: 80%+
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The friction force on \(2~\text{kg}\) block is:

           
1. \( \dfrac{15\sqrt{3}}{2} ~\text N\)

2. \(7 \sqrt{3}~\text N\)

3. \(10~\text N\)

4. none of these
Subtopic:  Friction |
 55%
Level 3: 35%-60%
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The system of blocks is pulled up by force as shown in the figure. The force exerted on the \(3\) kg block by the connecting string is:
1. \(80~\text{N}\) 2. \(60~\text{N}\)
3. \(40~\text{N}\) 4. \(100~\text{N}\)
Subtopic:  Application of Laws |
 70%
Level 2: 60%+
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A block is placed on a smooth horizontal surface, and forces are applied to it as shown in the diagram. Take \(g=10~\text{m/s}^2.\) The normal reaction acting on the block is:
           

1. \(100~\text N\)
2. \(60~\text N\)
3. \(40~\text N\)
4. \(20~\text N\)
Subtopic:  Tension & Normal Reaction |
 71%
Level 2: 60%+
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Four forces are acting at a point \(P\) in equilibrium as shown in the figure. If the ratio of force \(F_1\) to \(F_2\) is \(1:x,\) then the value of \(x \) is:
  
1. \(4\) 2. \(3\)
3. \(2\) 4. \(1\)
Subtopic:  Application of Laws |
 68%
Level 2: 60%+
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