Q. No.In a Young's double slit interference experiment the fringe pattern is observed on a screen placed at a distance \(D\) from the slits. The slits are separated by a distance \(d\) and are illuminated by monochromatic light of wavelength \(\lambda\). The minimum distance from the central point where intensity falls to \(\dfrac{1}{4}{th}\) of the maximum value:
1.
\(\dfrac{D\lambda}{2d}\)
2.
\(\dfrac{D\lambda}{3d}\)
3.
\(\dfrac{D\lambda}{4d}\)
4.
\(\dfrac{D\lambda}{5d}\)
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| Column-I | Column-II | ||
| (a) | If \({\Delta x}=\dfrac{\lambda}{3}\) | (p) | resultant intensity will be \(3I_0\) |
| (b) | If \(\phi = 60^{\circ}\) | (q) | resultant intensity will be \(I_0\) |
| (c) | If \({\Delta x}=\dfrac{\lambda}{4}\) | (r) | resultant intensity will be zero |
| (d) | If \(\phi = 90^{\circ}\) | (s) | resultant intensity will be \(2I_0\) |
| 1. | a(q), b(p), c(s), d(s) |
| 2. | a(s), b(p), c(s), d(q) |
| 3. | a(q), b(s), c(s), d(p) |
| 4. | a(s), b(r), c(q), d(r) |
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| 1. | \(\dfrac{\lambda}{d}\) | 2. | \(\dfrac{\lambda}{2d}\) |
| 3. | \(\dfrac{2\lambda}{d}\) | 4. | \(\dfrac{\lambda}{4d}\) |
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1. \(400\)
2. \(800\)
3. \(200\)
4. \(1600\)
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| 1. | \(135\) | 2. | \(180\) |
| 3. | \(320\) | 4. | \(428\) |
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| 1. | \(\dfrac{hD}{mvd}\) | 2. | \(\dfrac{hD}{2mvd}\) |
| 3. | \(\dfrac{2hD}{mvd}\) | 4. | \(\dfrac{3hD}{2mvd}\) |
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| 1. | \(\dfrac{\lambda f}{d}\) | 2. | \(\dfrac{2\lambda f}{d}\) |
| 3. | \(\dfrac{\lambda f}{2d}\) | 4. | \(\dfrac{\lambda f}{d\sqrt2}\) |
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| 1. | \(\dfrac{2d^2}{D}\) | 2. | \(\dfrac{2d^2}{3D}\) |
| 3. | \(\dfrac{d^2}{2D}\) | 4. | \(\dfrac{d^2}{6D}\) |
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| 1. | \(\alpha>\beta\) |
| 2. | \(\beta>\alpha\) |
| 3. | \(\alpha=\beta\) |
| 4. | the relation between \(\alpha~\&~\beta \) cannot be predicted. |
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| 1. | \(\dfrac{2d^2}{D}\) | 2. | \(\dfrac{d^2}{2D}\) |
| 3. | \(\dfrac{d^2}{D}\) | 4. | \(\dfrac{D^2}{d}\) |
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