A galvanometer having a coil resistance of 60Ω shows full scale deflection when a current of 1.0A passes through it. It can be converted into an ammeter to read currents upto 5.0A by 

1. putting in series resistance of 240Ω

2. putting in parallel resistance of 240Ω

3. putting in series resistance of 15Ω

4. putting in parallel resistance of 15Ω

Subtopic:  Conversion to Ammeter & Voltmeter |
 75%
Level 2: 60%+
NEET - 2009
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See the electrical circuit shown in this figure. Which of the following equation is a correct equation for it?

1. ε1-i1+i2R-i1r1=0

2. ε2-i2r2-ε1-i1r1=0

3. -ε2-i1+i2R+i2r2=0

4. ε1-i1+i2R+i1r1=0

Subtopic:  Kirchoff's Voltage Law |
 71%
Level 2: 60%+
NEET - 2009
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A current of 3A flows through the 2Ω resistor shown in the circuit. The power dissipated in the 5Ω resistor is

 

1. 4 W                                             
2. 2 W
3. 1 W                                             
4. 5 W

Subtopic:  Heating Effects of Current |
 79%
Level 2: 60%+
NEET - 2008
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A wire of a certain material is stretched slowly by ten per cent. Its new resistance and specific resistance become respectively 1. .

1.  \(\text {2 times, 1.1 times}\)
2.  \(\text {1.21 times, same}\)
3.  \(\text{both remain the same}\)
4.  \(\text {1.1 times, 1.1 times}\)

Subtopic:  Derivation of Ohm's Law |
 83%
Level 1: 80%+
NEET - 2008
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A cell can be balanced against 110cm and 100 cm of potentiometer wire, respectively with and without being short-circuited through a resistance of 10Ω. Its internal resistance is 

1. 1.0 Ω

2. 0.5 Ω

3. 2.0 Ω

4. zero 

Subtopic:  Grouping of Cells |
 78%
Level 2: 60%+
NEET - 2008
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In the circuit shown, the current through the \(4~\Omega\) resistor is \(1~\text{A}\) when the points \(P\) and \(M\) are connected to a DC voltage source. The potential difference  between the points \(M\) and \(N\) is: 


1. \(1.5~\text{V}\)
2. \(1.0~\text{V}\)
3. \(0.5~\text{V}\)
4. \(3.2~\text{V}\)

Subtopic:  Kirchoff's Voltage Law |
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Level 2: 60%+
NEET - 2008
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A galvanometer of resistance \(50~\Omega\) is connected to a battery of \(3\) V along with a resistance of \(2950~\Omega\) in series. A full-scale deflection of \(30\) divisions is obtained in the galvanometer. In order to reduce this deflection to \(20\) divisions, the resistance in series should be:
1. \(5050~\Omega\)
2. \(5550~\Omega\)
3. \(6050~\Omega\)
4. \(4450~\Omega\)

Subtopic:  Conversion to Ammeter & Voltmeter |
 63%
Level 2: 60%+
NEET - 2008
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A capacitor of capacitance 5 μF is connected as shown in the figure. The internal resistance of the cell is 0.5 Ω. The amount of charge on the capacitor plate is?

1. 0 μC

2. 5 μC

3. 10 μC

4. 25 μC

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In the circuit here, the steady state voltage across capacitor C is a fraction of the battery e.m.f. The fraction is decided by 

1. R1 only

2. R1 and R2 only

3. R1 and R3 only

4. R1, R2 and R3

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In the figure below, what is the potential difference between the point A and B and between B and C respectively in steady state 

(1) VAB=VBC=100V

(2) VAB=75V,VBC=25V

(3) VAB=25V,VBC=75V

(4) VAB=VBC=50V

Level 3: 35%-60%
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