An ideal inductor-resistor-battery circuit is switched on at \(t=0~\text{s}\). At time \(t\), the current is \(i=i_0\left(1-e^{\left(-\frac{t}{\tau}\right)}\right)\text{A}\), where \(i_0\) is the steady-state value. The time at which the current becomes \(0.5i_0\) is: [Given \(\text{ln}(2)= 0.693\)]
1. \(6.93 \times 10^3 ~\text{s}\)
2. \(6.93~\text{ms}\)
3. \(69.3~\text{s}\)
4. \(6.93~\text{s}\)
Subtopic:  LR circuit |
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The resistance in the following circuit is increased at a particular instant. At this instant the value of resistance is \(10~\Omega.\) The current in the circuit will be:

1. \(i = 0.5~\text{A}\) 2. \(i > 0.5~\text{A}\)
3. \(i < 0.5~\text{A}\) 4. \(i = 0\)
Subtopic:  LR circuit |
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The key \(K\) is inserted at time \(t=0\). The initial \((t=0)\) and final \(t\rightarrow \infty\) currents through the battery are:
                              

1. \(\frac{1}{15}~\text{A},~\frac{1}{10}~\text{A}\)
2. \(\frac{1}{10}~\text{A},~\frac{1}{15}~\text{A}\)
3. \(\frac{2}{15}~\text{A},~\frac{1}{10}~\text{A}\)
4. \(\frac{1}{15}~\text{A},~\frac{2}{25}~\text{A}\)

Subtopic:  LR circuit |
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The current in the branch of a circuit shown below increases at a rate of \(3\) A/s. At the instant when the current in the wire is \(2\) A, the potential drop from \(a\) to \(b\) is:

              
1. \(26~\text{V}\)
2. \(14~\text{V}\)
3. \(16~\text{V}\)
4. \(6~\text{V}\)

Subtopic:  LR circuit |
 68%
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