If the ratio of diameters, lengths and Young's modulus of steel and copper wires shown in the figure are \(p,\) \(q\) and \(s\) respectively, then the corresponding ratio of increase in their lengths would be:
                      
1. \(\dfrac{5 q}{\left(7 {sp}^2\right)} \) 2. \(\dfrac{7 q}{\left(5 sp^2\right)} \)
3. \(\dfrac{2 q}{(5 s p)} \) 4. \(\dfrac{7 q}{(5 s p)}\)
Subtopic:  Young's modulus |
 79%
From NCERT
NEET - 2013
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Steel and copper wires of the same length and area are stretched by the same weight one after the other. Young's modulus of steel and copper are \(2\times10^{11} ~\text{N/m}^2\) and  \(1.2\times10^{11}~\text{N/m}^2.\) The ratio of increase in length is: 

1. \(2 \over 5\) 2. \(3 \over 5\)
3. \(5 \over 4\) 4. \(5 \over 2\)
Subtopic:  Young's modulus |
 92%
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A metallic rope of diameter \(1~ \text{mm}\) breaks at \(10 ~\text{N}\) force. If the wire of the same material has a diameter of \(2~\text{mm},\) then the breaking force is:

1. \(2.5~\text{N}\)  2. \(5~\text{N}\) 
3. \(20~\text{N}\)  4. \(40~\text{N}\) 

Subtopic:  Young's modulus |
 74%
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The Young's modulus of a wire is numerically equal to the stress at a point when:

1. The strain produced in the wire is equal to unity.
2. The length of the wire gets doubled.
3. The length increases by \(100\%.\)
4. All of these.
Subtopic:  Young's modulus |
 75%
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In the CGS system, Young's modulus of a steel wire is \(2\times 10^{12}~\text{dyne/cm}^2.\) To double the length of a wire of unit cross-section area, the force required is:
1. \(4\times 10^{6}~\text{dynes}\)
2. \(2\times 10^{12}~\text{dynes}\)
3. \(2\times 10^{12}~\text{newtons}\)
4. \(2\times 10^{8}~\text{dynes}\)

Subtopic:  Young's modulus |
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Two wires are made of the same material and have the same volume. The first wire has a cross-sectional area \(A\) and the second wire has a cross-sectional area \(3A\). If the length of the first wire is increased by \(\Delta l\) on applying a force \(F\), how much force is needed to stretch the second wire by the same amount?

1. \(9F\) 2. \(6F\)
3. \(4F\) 4. \(F\)
Subtopic:  Young's modulus |
 77%
From NCERT
NEET - 2018
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A wire of length \(L,\) area of cross section \(A\) is hanging from a fixed support. The length of the wire changes to \({L}_1\) when mass \(M\) is suspended from its free end. The expression for Young's modulus is:

1. \(\dfrac{{Mg(L}_1-{L)}}{{AL}}\) 2. \(\dfrac{{MgL}}{{AL}_1}\)
3. \(\dfrac{{MgL}}{{A(L}_1-{L})}\) 4. \(\dfrac{{MgL}_1}{{AL}}\)
Subtopic:  Young's modulus |
 79%
From NCERT
NEET - 2020
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Copper of fixed volume \(V\) is drawn into a wire of length \(l.\) When this wire is subjected to a constant force \(F,\) the extension produced in the wire is \(\Delta l.\) Which of the following graphs is a straight line?
1. \(\Delta l ~\text{vs}~\dfrac{1}{l}\)
2. \(\Delta l ~\text{vs}~l^2\)
3. \(\Delta l ~\text{vs}~\dfrac{1}{l^2}\)
4. \(\Delta l ~\text{vs}~l\)
Subtopic:  Young's modulus |
 72%
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AIPMT - 2014
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A wire of length \(\mathrm{L}\) is hanging from a fixed support. The length changes to \(\mathrm{L}_{1}\) and \(\mathrm{L}_{2}\) when masses \(1\) kg and \(2\) kg are suspended respectively from its free end. The value of \(\mathrm{L}\) is equal to: 
1. \(\sqrt{\mathrm{L}_{1} \mathrm{~L}_{2}} \)
2. \(\frac{\mathrm{L}_{1}+\mathrm{L}_{2}}{2} \)
3. \(2 \mathrm{~L}_{1}-\mathrm{L}_{2} \)
4. \(3 \mathrm{~L}_{1}-2 \mathrm{~L}_{2}\)
Subtopic:  Young's modulus |
 78%
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A student plots a graph from his readings on the determination of Young modulus of a metal wire but forgets to put the labels (figure). The quantities on X and Y-axes may be respectively,

               

(a) weight hung and length increased
(b) stress applied and length increased
(c) stress applied and strain developed
(d) length increased and the weight hung


Choose the correct option:

1. (a) and (b)
2. (b) and (c)
3. (a), (b) and (d)
4. all of these
Subtopic:  Young's modulus |
 58%
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