- 1(current)
Q. No.Two wires of copper having length in the ratio of \(4:1\) and radii ratio of \(1:4\) are stretched by the same force. The ratio of longitudinal strain in the two will be:
| 1. | \(1:16\) | 2. | \(16:1\) |
| 3. | \(1:64\) | 4. | \(64:1\) |
Subtopic: Hooke's Law |
63%
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Hooke's law is applicable for:
| 1. | elastic materials only | 2. | plastic materials only |
| 3. | elastomers only | 4. | all of these |
Subtopic: Hooke's Law |
72%
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The length of an elastic string is \(a\) metre when the longitudinal tension is \(4\) N and \(b\) metre when the longitudinal tension is \(5\) N. The length of the string in metre when the longitudinal tension is \(9\) N will be:
| 1. | \(a-b\) | 2. | \(5b-4a\) |
| 3. | \(2b-\frac{1}{4}a\) | 4. | \(4a-3b\) |
Subtopic: Hooke's Law |
77%
From NCERT
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Two wires of copper having the length in the ratio \(4:1\) and their radii ratio as \(1:4\) are stretched by the same force. The ratio of longitudinal strain in the two wires will be:
1. \(1:16\)
2. \(16:1\)
3. \(1:64\)
4. \(64:1\)
Subtopic: Hooke's Law |
64%
From NCERT
To view explanation, please take trial in the course.
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Hints
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On applying stress of \(20 \times 10^8~\text{Nm}^{-2}\) the length of a perfectly elastic wire is doubled. It's Young’s modulus will be:
1. \(40 \times 10^8~\text{Nm}^{-2}\)
2. \(20 \times 10^8~\text{Nm}^{-2}\)
3. \(10 \times 10^8~\text{Nm}^{-2}\)
4. \(5 \times 10^8~\text{Nm}^{-2}\)
1. \(40 \times 10^8~\text{Nm}^{-2}\)
2. \(20 \times 10^8~\text{Nm}^{-2}\)
3. \(10 \times 10^8~\text{Nm}^{-2}\)
4. \(5 \times 10^8~\text{Nm}^{-2}\)
Subtopic: Hooke's Law |
71%
From NCERT
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