Q. No.The specific heat of a gas in an isothermal process is:
| 1. | Infinite | 2. | Zero |
| 3. | Negative | 4. | Remains constant |
1. \(\frac{\eta}{2}\)
2. \(\eta\)
3. \(2\eta\)
4. \(3\eta\)
Match the following:
| Column I | Column II | ||
| \(P\). | Process-I | \(\mathrm{a}\). | Adiabatic |
| \(Q\). | Process-II | \(\mathrm{b}\). | Isobaric |
| \(R\). | Process-III | \(\mathrm{c}\). | Isochoric |
| \(S\). | Process-IV | \(\mathrm{d}\). | Isothermal |
| 1. | \(P \rightarrow \mathrm{a}, Q \rightarrow \mathrm{c}, R \rightarrow \mathrm{d}, S \rightarrow \mathrm{b}\) |
| 2. | \(P \rightarrow \mathrm{c}, Q \rightarrow \mathrm{a}, R \rightarrow \mathrm{d}, S \rightarrow b\) |
| 3. | \(P \rightarrow \mathrm{c}, Q \rightarrow \mathrm{d}, R \rightarrow \mathrm{b}, S \rightarrow \mathrm{a}\) |
| 4. | \(P \rightarrow \mathrm{c}, Q \rightarrow \mathrm{d}, R \rightarrow \mathrm{b}, S \rightarrow \mathrm{a}\) |
The pressure-temperature \((P\text-T)\) graph for two processes, \(A\) and \(B,\) in a system is shown in the figure. If \(W_1\) and \(W_2\) are work done by the gas in process \(A\) and \(B\) respectively, then:
| 1. | \(W_{1}=W_2\) | 2. | \(W_{1}<W_2\) |
| 3. | \(W_{1}>W_2\) | 4. | \(W_{1}= - W_2\) |
In a cyclic process, the internal energy of the gas:
| 1. | increases | 2. | decreases |
| 3. | remains constant | 4. | becomes zero |
In the following figures, four curves A, B, C and D, are shown. The curves are:
| 1. | isothermal for A and D while adiabatic for B and C. |
| 2. | adiabatic for A and C while isothermal for B and D. |
| 3. | isothermal for A and B while adiabatic for C and D. |
| 4. | isothermal for A and C while adiabatic for B and D. |
1. \(0\)
2. \(5~\text{J}\)
3. \(1~\text{J}\)
4. \(3~\text{J}\)
\(1~\text g\) of water of volume \(1~\text{cm}^3\) at \(100^\circ \text{C}\) is converted into steam at the same temperature under normal atmospheric pressure \(\approx 1\times10^{5}~\text{Pa}.\) The volume of steam formed equals \(1671~\text{cm}^3.\) If the specific latent heat of vaporization of water is \(2256~\text{J/g},\) the change in internal energy is:
1. \(2423~\text J\)
2. \(2089~\text J\)
3. \(167~\text J\)
4. \(2256~\text J\)
The volume \((V)\) of a monatomic gas varies with its temperature \((T),\) as shown in the graph. The ratio of work done by the gas to the heat absorbed by it when it undergoes a change from state \(A\) to state \(B\) will be:
| 1. | \(\dfrac{2}{5}\) | 2. | \(\dfrac{2}{3}\) |
| 3. | \(\dfrac{1}{3}\) | 4. | \(\dfrac{2}{7}\) |
1. \(V_1= V_2\)
2. \(V_1> V_2\)
3. \(V_1< V_2\)
4. \(V_1\ge V_2\)
© 2025 GoodEd Technologies Pvt. Ltd.