The metre bridge shown is in a balanced position with \(\frac{P}{Q} = \frac{l_1}{l_2}\). If we now interchange the position of the galvanometer and the cell, will the bridge work? If yes, what will be the balanced condition?
1. | Yes, \(\frac{P}{Q}=\frac{l_1-l_2}{l_1+l_2}\) | 2. | No, no null point |
3. | Yes, \(\frac{P}{Q}= \frac{l_2}{l_1}\) | 4. | Yes, \(\frac{P}{Q}= \frac{l_1}{l_2}\) |
The Wheatstone bridge shown in the figure below is balanced when the uniform slide wire \(AB\) is divided as shown. Value of the resistance \(X\) is:
1. \(3~\Omega\)
2. \(4~\Omega\)
3. \(2~\Omega\)
4. \(7~\Omega\)