1. | ![]() |
2. | ![]() |
3. | ![]() |
4. | ![]() |
1. | \(1~\text V\) | 2. | \(2.1~\text V\) |
3. | \(3.1~\text V\) | 4. | Zero |
1. | the stopping potential will be \(0.2\) volt. |
2. | the stopping potential will be \(0.6\) volt. |
3. | the saturation current will be \(6~\text{mA}.\) |
4. | the saturation current will be \(18~\text{mA}.\) |
The correct graph between photoelectric current \((i)\) and intensity \((I)\) is:
1. | |
2. | |
3. | 4. | |
1. | ![]() |
2. | ![]() |
3. | ![]() |
4. | ![]() |
1. | \(A\) | 2. | \(B\) |
3. | \(C\) | 4. | None of these |
In the case of the photoelectric effect:
1. | Since photons are absorbed as single (discrete) units, there is no significant time delay in the emission of photoelectrons. |
2. | According to Einstein, the critical frequency \(\nu_{0} =\dfrac{e\phi }{h},\) where \(\phi\) is the work function and \(h\) is Planck’s constant. When light with this frequency \((\nu_0)\) hits the material, it causes electrons to be ejected with the maximum possible kinetic energy. |
3. | Only a small fraction of the incident photons succeed in ejecting photoelectrons, while the majority are absorbed by the system as a whole and generate thermal energy. |
4. | The maximum kinetic energy of the electrons depends on the intensity of the radiation. |
1. | \(1.00\) | 2. | \(1.02\) |
3. | \(1.04\) | 4. | \(0.98\) |