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Q. No.1 mol of monoatomic ideal gas expanded adiabatically against a constant pressure of 2 atm from 10L to 20L. The correct option for the above process is:
1. q = 20 L-atm
2. \(\Delta U = 0 \)
3. \(\Delta U = -20 ~\text L~\text {atm} \)
4. \(\text w = 10 ~\text L~ \text {atm} \)
Subtopic: First Law of Thermodynamics |
82%
From NCERT
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A system is taken from state \(a\) to state \(c\) by two paths \(adc\) and \(abc\) as shown in the figure. The internal energy at \(a\) is \({U}_{a}=10~\text{J}.\) Along the path \(adc\) the amount of heat absorbed \(\delta Q_1=50~\text{J}\) and the work obtained \(\delta W_1=20~\text{J}\) whereas along the path \(abc\) the heat absorbed \(\delta Q_2 = 36~\text{J}.\) The amount of work along the path \(abc\) is:
| 1. | \(10~\text{J}\) | 2. | \(12~\text{J}\) |
| 3. | \(36~\text{J}\) | 4. | \(6~\text{J}\) |
Subtopic: First Law of Thermodynamics |
81%
From NCERT
NEET - 2013
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Which of the following relations does not give the equation of an adiabatic process, where terms have their usual meaning?
1. \({P}^{1-\gamma}{T}^{\gamma}= \text{constant}\)
2. \({PV}^{\gamma}=\text{constant}\)
3. \({TV}^{\gamma-1}= \text{constant}\)
4. \({P}^{\gamma} {T}^{1-\gamma}=\text{constant}\)
1. \({P}^{1-\gamma}{T}^{\gamma}= \text{constant}\)
2. \({PV}^{\gamma}=\text{constant}\)
3. \({TV}^{\gamma-1}= \text{constant}\)
4. \({P}^{\gamma} {T}^{1-\gamma}=\text{constant}\)
Subtopic: Types of Processes |
77%
From NCERT
NEET - 2013
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| Statement I: | ∆S total i.e., ∆Ssys + ∆Ssurr is zero for the irreversible process. |
| Statement II: | Total entropy change for the system and surrounding of a spontaneous process is zero. |
| 1. | Statement I is False but Statement II is True. |
| 2. | Both Statement I and Statement II are True. |
| 3. | Both Statement I and Statement II are False. |
| 4. | Statement I is True but Statement II is False. |
Subtopic: Spontaneity & Entropy |
54%
From NCERT
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If bond enthalpies of \(C-C,C-H,O=O,C=O \) and \(O-H \) are
a, b, c, d, and e respectively, then the heat of combustion of ethane will be:
1. \(6 b+\frac{7}{2} c+a-2 d-3e \)
2. \(b+c+a-4 d-3e \)
3. \(6 b+\frac{7}{2} c+a-4 d-6e \)
4. \(6 b+7 c+a-4 d-6e \)
a, b, c, d, and e respectively, then the heat of combustion of ethane will be:
1. \(6 b+\frac{7}{2} c+a-2 d-3e \)
2. \(b+c+a-4 d-3e \)
3. \(6 b+\frac{7}{2} c+a-4 d-6e \)
4. \(6 b+7 c+a-4 d-6e \)
Subtopic: Thermochemistry |
77%
From NCERT
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For \(\Delta G <0 \) , a reaction is spontaneous only if :
| 1. | Pressure is constant. |
| 2. | Temperature is constant. |
| 3. | Both pressure and temperature are constant. |
| 4. | Both temperature and volume are constant. |
Subtopic: Spontaneity & Entropy |
57%
From NCERT
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3 moles of helium gas at 1 bar is compressed reversibly and isothermally at 400 K to 10 bar pressure. The work done (in J) on the system is: (Given: \(R= 8.314 ~J K^{-1}~ mol^{-1}\) )
| 1. | \(2.29 \times 10^4 \) | 2. | \(2.29 \times 10^{-4} \) |
| 3. | \(-2.29 \times 10^4 \) | 4. | \(-2.29 \times 10^{-4} \) |
Subtopic: First Law of Thermodynamics |
58%
From NCERT
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An ideal gas follows a process described by the equation \(PV^2=C\) from the initial \((P_1, V_1, T_1)\) to final \((P_2, V_2, T_2)\) thermodynamics states, where \(C\) is a constant. Then:
| 1. | \(\text{If}~P_1>P_2~\text{then}~T_1<T_2\) |
| 2. | \(\text{If}~V_2>V_1~\text{then}~T_2>T_1\) |
| 3. | \(\text{If}~V_2>V_1~\text{then}~T_2<T_1\) |
| 4. | \(\text{If}~P_1>P_2~\text{then}~V_1>V_2\) |
Subtopic: Types of Processes |
From NCERT
NEET - 2022
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Identify correct match using Column I & Column II
| Column I | Column II | ||
| (i) | Spontaneous process | (a) | Isothermal and isobaric process |
| (ii) | \(\Delta H^\circ\) | (b) | \(\Delta H<0 \) |
| (iii) | \(\Delta T=0, \Delta P=0 \) | (c) | \(\Delta G<0 \) |
| (iv) | Exothermic process | (d) | (Bond energy of reactant) - (Bond energy of product) |
| I | II | III | IV | |
| 1. | c | d | a | b |
| 2. | b | a | c | d |
| 3. | d | b | c | d |
| 4. | a | d | b | c |
Subtopic: First Law of Thermodynamics | Spontaneity & Entropy | Gibbs Energy Change |
94%
From NCERT
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For the given cycle, the work done during the isobaric process is:
1. \(200\) J
2. zero
3. \(400\) J
4. \(600\) J
1. \(200\) J
2. zero
3. \(400\) J
4. \(600\) J
Subtopic: Work Done by a Gas |
56%
From NCERT
NEET - 2023
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NEET 2025 - Target Batch
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