A substance on treatment with dil. \(H_2SO_4\) liberates a colourless gas that produces
(i) turbidity with baryta water
(ii) turns acidified dichromate solution green
The reaction indicates the presence of:
1. \(CO^{2-}_3\)
2. \(S^{2-}\)
3. \(SO^{2-}_3\)
4. \(NO^{-}_2\)
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The brown ring test for NO3- is enabled due to the formation of the complex ion with the formula:
1. \(\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+} \)
2. \(\mathrm{Fe}\left[\mathrm{NO}(\mathrm{CN})_5\right]^{2-} \)
3. \(\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_5 \mathrm{NO}\right]^{2+} \)
4. \(\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)(\mathrm{NO})_5\right]^{2+} \)
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Sodium nitroprusside, when added to an alkaline solution of sulphide ions, produces purple colour ion due to formation of:
1. \(Na[Fe(H_2O)_5NOS]2 \)
2. \(Na_2[Fe(H_2O)_5NOS] \)
3. \(Na_3[Fe(CN)_5NOS] \)
4. \(Na_4[Fe(CN)_5NOS] \)
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Two test tubes containing nitrate and bromide are treated separately with conc. H2SO4. Brown fumes, thus evolved, are passed in water. The water will be coloured by vapours evolved from the test tube containing:
1. Nitrate
2. Bromide
3. Both (a) and (b)
4. None of these
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